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tenemos q...en este ejercicio realice lo sieguiente <br />tenemos que C=10 cm<br />a=5cm<br />b=x<br />entonces<br />b=√10al cuadrado -5 al cuadrado<br />b=√100-25<br />b=√75<br />b=8.66<br /><br />entonces aplicamos esta regla a=b*h/2 o sea base por altura entre dos<br /><br />a=5*8.66/2=21.65<br /><br />R. el area del triangulo equilatero es de 21.65 cm cuadrados.cristian martinezhttps://www.blogger.com/profile/02987601703242728903noreply@blogger.comtag:blogger.com,1999:blog-4272755674573938743.post-50488329843258937112011-05-23T19:11:45.157-07:002011-05-23T19:11:45.157-07:00AMANDA PATRICIA GUTIERREZ SECCION"H"
El...AMANDA PATRICIA GUTIERREZ SECCION"H"<br /><br />El problema nos dice que calculemos el area de un triangulo equilatero:<br /><br />El teorema de pitagoras nos dice<br /><br />b=√c2-a2<br />b=√102-52<br />b=√100-25<br />b=√75<br />b=8.66<br /><br /> usamos la formula del triangulo:<br />b.h/2<br />5x8.66/2<br />R=/ 21.65 es el area dAmanda Patriciahttps://www.blogger.com/profile/01823681823442185029noreply@blogger.comtag:blogger.com,1999:blog-4272755674573938743.post-87784395974118896992011-05-22T19:34:12.848-07:002011-05-22T19:34:12.848-07:00Bueno lo primero que tenemos que hacer es encontra...Bueno lo primero que tenemos que hacer es encontrar el valor de la altura y para sacarlo lo que hacemos es que utilizamos Pitágoras:<br />c^2= a^2+b^2<br />a^2= c^2-b^2<br />a= raiz de 75 y si simplificamos el radical tenemos 5 raiz de 3.<br />Ahora sacamos el área con la formula que es A=1/2bh<br />A=1/2(5)(8.66)<br />A=21.65Bayronhttps://www.blogger.com/profile/14411444992321908351noreply@blogger.comtag:blogger.com,1999:blog-4272755674573938743.post-6692545375863600422011-05-22T10:13:03.799-07:002011-05-22T10:13:03.799-07:00para encontrar la altura podemos aplicar el teorem...para encontrar la altura podemos aplicar el teorema de Pitagoras ya que conocemos el valor de c=que seria la hipotenusa y a=5 que seria un cateto solo nos falta la medida del cateto b=?.<br />c2=a2+b2 despejando para b nos queda b2=c2-a2,<br />b2=c2-a2<br />b2=(10)2-(5)2<br />b2=100-25<br />_/b2=_/75<br />b=8.66<br /><br />entonces la altura del triangulo es 8.66cm (b=h).<br /><br />valores del triangulo:<br />(altura)h=8.66cm, (base)b=10cm.<br />bXh/2 = 8.66cm X 10cm/2 = 86.6cm2/2= 43.3cm2.<br /><br />el area del triangulo es: 43.3cm2<br /><br />Christian Javier Sanchez, seccion "A".christian sanchezhttps://www.blogger.com/profile/17677912137409175893noreply@blogger.com